|
You can increase search results by using partial words (ie. 'orga% cott%' for 'organic cotton') SELECT COUNT(DISTINCT [BS].company_name) FROM [BS] Inner Join BS_A1 ON [BS].ID = BS_A1.Referral_ID WHERE (Category1 LIKE 'Building%' OR Category1 LIKE 'Alternative%' OR Category1 LIKE 'Garden%' OR Category1 LIKE 'Arch%' OR Category1 LIKE 'Salvage%' )--0--Name-or-product--Name-or-product |


Go to


