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You can increase search results by using partial words (ie. 'orga% cott%' for 'organic cotton') SELECT COUNT(DISTINCT [AO].company_name) FROM [AO] Inner Join AO_Hotel ON [AO].ID = AO_Hotel.Referral_ID WHERE (Category1 LIKE 'Travel%' OR Category1 LIKE 'Hotel%' )--0--Name-or-product--Name-or-product |

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